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Calculate belt power, belt speed, effective pull, and belt tension with our Belt Power Transmission Calculator. Get fast, simple results online.
| Equation | Purpose | Notes |
|---|---|---|
| v = πDN ÷ 60 | Belt speed | D in m, N in rpm → v in m/s |
| Fe = T1 − T2 | Effective pull | — |
| P = Fe × v | Transmitted power | Watts; ÷1000 for kW |
| T1/T2 = e^(μθ) | Flat-belt friction ratio | Capstan/Euler relation, limiting slip |
| Tc = m·v² | Centrifugal tension | m = belt mass per unit length |
| (T1−Tc)/(T2−Tc) = e^(μθ) | Friction ratio with centrifugal tension | Needed at high belt speeds |
The Belt Power Transmission Calculator helps you find the power carried by a belt drive. It uses belt speed, tight-side tension, and slack-side tension to find transmitted power.
You can also use it to find belt tension from the friction ratio. The calculator supports a basic belt system and a system with centrifugal tension.
This makes it useful for belt drive power calculation, V-belt studies, timing belt checks, and basic mechanical design work.
The main belt power transmission formula is:
Power = (T1 − T2) × v
Where:
T1 = tight-side belt tension in N
T2 = slack-side belt tension in N
v = belt speed in m/s
Power is first found in watts. To convert watts to kilowatts:
Power (kW) = [(T1 − T2) × v] ÷ 1000
The calculator can also find belt speed from pulley size and speed:
v = π × D × N ÷ 60
Here, D is pulley diameter in meters and N is pulley speed in rpm.
The effective belt pull is:
Fe = T1 − T2
For the belt tension ratio, the calculator uses:
R = e^(μθ)
T2 = Fe ÷ (R − 1)
T1 = T2 + Fe
Here, μ is the coefficient of friction and θ is the angle of contact in radians.
When centrifugal tension is included:
Tc = m × v²
Then:
T2 = Fe ÷ (R − 1) + Tc
T1 = T2 + Fe
These formulas are also useful when studying V belt power transmission, timing belt tension, and other belt drive systems. The exact belt design may need extra factors based on belt type and manufacturer data.
This online tool can help with quick belt drive power calculation, V belt tension calculation, and basic belt conveyor power calculation work.
Suppose a belt has a tight-side tension of 500 N and a slack-side tension of 200 N.
The pulley diameter is 0.6 m, and the pulley speed is 400 rpm.
First, find belt speed:
v = π × 0.6 × 400 ÷ 60
v = 12.566 m/s
Now find effective pull:
Fe = 500 − 200
Fe = 300 N
Next, calculate transmitted power:
P = 300 × 12.566
P = 3769.8 W
Convert watts to kilowatts:
P = 3769.8 ÷ 1000
P = 3.77 kW
So, the belt transmits about 3.77 kW of power.
The same basic approach can help explain a belt conveyor motor power calculation. However, a real conveyor also needs factors such as load, friction, incline, pulley losses, and efficiency.
The Belt Power Transmission Calculator gives a fast way to calculate belt power and belt tension. Its main formula is Power = (T1 − T2) × v.
It also supports pulley diameter and rpm inputs, friction-based tension ratios, and centrifugal tension. This makes it useful for basic belt drive and mechanical power calculations.
For detailed machine design, always check the belt manufacturer’s ratings and engineering safety requirements.
The main formula is:
Power = (T1 − T2) × v
T1 is tight-side tension, T2 is slack-side tension, and v is belt speed.
Use:
v = π × D × N ÷ 60
D must be in meters, and N must be in rpm.
Effective belt pull is the difference between tight-side and slack-side tension:
Fe = T1 − T2
The basic power relation is:
P = (T1 − T2) × v
Actual V-belt selection also depends on belt type, pulley size, speed, wrap angle, and manufacturer power ratings.
Yes. The calculator can calculate T1 and T2 from effective pull and the friction ratio. It can also include centrifugal tension.
Centrifugal tension is caused by the belt's mass moving at speed. The calculator uses:
Tc = m × v²
It can be used for basic belt power calculations. A complete conveyor motor power calculation needs additional data, such as belt load, conveyor length, slope, resistance, and efficiency.
Not always. Motor power can be higher because belts, pulleys, bearings, and gearboxes can create power losses. System efficiency should be considered for a complete design.